2 sin 2theta = v3 then the value of theta is what
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2 sin2θ = √3
sin2θ = √3/2
2θ = sin^(-) (√3)/2)
2θ = sin^(-) (π/3)
2θ = π/3
θ = π/3 × 2 = π/6
θ = π/6
The value for θ is π/6 or 30°
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Answer:
2 sin2θ = √3
sin2θ = √3/2
2θ = sin^(-) (√3)/2)
2θ = sin^(-) (π/3)
2θ = π/3
θ = π/3 × 2 = π/6
θ = π/6
The value for θ is π/6 or 30°
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