Question

(2 sin 30. Cosec 30)
. tan 45 cos 0)
Simplify
( Cot 45. sin 90.
2 sec 0. sec 60)​

Answer 1

Step-by-step explanation:

given (2 sin 30. cosec 30).(tan 45 . cos 0)

we know some and cosec are multiplicative inverses

so sin 30. cosec 30 =1

we know tan 45 =1 & cos 0=1

therefore (2 sin 30. cosec 30).(tan 45 . cos 0)=2(1)(1)=

( cot 45. sin 90) ( 2 sec 0. sec 60)

we know cot 45 =1 and sin 90 =1

sec 0=1 & sec 60= 2

therefore (cot 45. sin 90) (2 sec 0. sec 60)=(1)(2)(1)(2)=4