2 sin 30° - 3 cos 45º+tan? 60° + 3 sin? 90º =
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Given 2sin
2
30
∘
−3cos
2
45
∘
+tan
2
60
∘
=2(
2
1
)
2
−3(
2
1
)
2
+(
3
)
2
[∵cos45
∘
=
2
1
,sin30
∘
=
2
1
,tan60
∘
=
3
]
=
4
2
−
2
3
+3
=
2
1
−
2
3
+
2
3×2
=
2
1
−
2
3
+
2
6
=
2
4
=2
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