Question

2(sin^45+cot^30)-3(cosec^60-sec^60)=15

Answer 1

Hey, I found something missing in your question.

I think you question should have been:

2(sin²45+cot²30)-3(cosec²60-sec²60)=15

Am I right?

If so, then please refer attachment.

In the first step i.e., the first step with '=⟩', I have replaced the angle values with the respective trigonometrical ratios to find the answer.

In the attachments, I have also provided some common angles and their trigonometrical ratios.

Hope this helped...