Question

2(sin^6 theta+cos^6 theta)-3(sin^4 theta+cos^4 theta)+1=0..prove this

Answer 1

2 into into sin cube theta the whole square + cos cube theta ka whole square minus 3 into sin square theta ka whole square + cos square theta ka whole square + 1 = 20 nextstep as we know sin square theta + cos square theta equals to 1 Putta sin cube theta cos square A + cos cube theta ka whole square equals to one and sin square theta whole square + cos square theta the whole square equals to 1 then the last chapter 2 into 1 minus 3 into 1 + 1 = 2 0 3 - 3 = 0

Answer 2

Answer:

Step-by-step explanation:

The detailed explanation is shown in Attached Figure .