2(sin^6theta+cos^6theta)-3(sin^4theta+cos^4theta)
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2(sin⁶θ+cos⁶θ)-3(sin⁴θ+cos⁴θ)
= 2{(sin²θ)³+(cos²θ)³}-3{(sin²θ)²+(cos²θ)²}
= 2{(sin²θ+cos²θ)³-3sin²θcos²θ(sin²θ+cos²θ)}-3{(sin²θ+cos²θ)²-2sin²θcos²θ}
=2(1-3sin²θcos²θ)-3(1-2sin²θcos²θ)
=2-6sin²θcos²θ-3+6sin²θcos²θ
=-1
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