Question

2(sin^6x+cos^6x)-3(sin^4x+cos^4x)+1 =

Answer 1

Hey !!!

From LHS
2 ( sin^6¢ +cos^6) -3(sin⁴¢ + cos⁴¢) +1

=> 2 {(sin²¢)³ + (cos²¢)³ -3{(sin²¢ )² +(cos²¢)² } + 1

•°•a³ + b³ = (a + b )(a² +b² -ab) and a²+b²= (a+b)²-2ab applying those twoformula

=> 2 {(sin²¢ + cos²¢) ²-2sin²¢×cos²¢ --sin²¢ ×cos²¢ -3{(sin²¢ +cos²¢)² -2sin²¢ ×cos²¢ }+1

=> 2{(1 - 3sin²¢ ×cos²¢ - 3 +6sin²¢ ×cos²¢) +1

=> 2 - 6sin²¢×cos²¢ - 3 -6sin²¢×cos²¢ +1

=>3 - 3 -6sin²¢×cos²¢ -6sin²¢ ×cos²¢

=> 0 Answer

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hope it helps you!!!!

@Rajukumar111