Question

2 Sin 7 theta cos 3 theta is equal to ​

Answer 1

Step-by-step explanation:

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Answer 2

Given:

$2Sin(7\theta)Cos(3\theta)$

To find:

The value of $2Sin(7\theta)Cos(3\theta)$

Solution:

$2Sin(7\theta)Cos(3\theta)$

We know that

$2SinACos B=Sin(A+B)+Sin(A-B)$

Using the formula

$2Sin(7\theta)Cos(3\theta)=Sin(7\theta+3\theta)+Sin(7\theta-3\theta)$

$2Sin(7\theta)Cos(3\theta)=Sin(10\theta)+Sin(4\theta)$

$2Sin(7\theta)Cos(3\theta)=Sin(10\theta)+Sin(4\theta)$

Hence, the value of $2Sin(7\theta)Cos(3\theta)=Sin(10\theta)+Sin(4\theta)$