2 sin a upon sec a + tan a - 1 + cos a upon cosec a + cot a minus 1 is equal to 1
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Dear student
(SinA * cosA )/(1 + sinA - cosA) + (cosA* sinA)/(1 + cosA - sinA)
= (SinA * cosA) [1/(1 + sinA - cosA) + 1/(1 + cosA -sinA)]
On taking LCM and then solving
= 2 sinA cosA/ 2 sinA cosA
= 1 = RHS
Hence proved
Regards
Arun (askIITians forum expert)
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