Question

2 sin sin 2θ/cosθ + cos 3θ = tan 2θ tanθ

Answer 1

Answer:

2cos

3

θ−cosθ

sinθ−2sin

3

θ

=

cosθ(2cos

2

θ−1)

sinθ(1−2sin

2

θ)

=

cosθ(cos2θ)

sinθ(cos2θ)

since 1−2sin

2

θ=2cos

2

θ−1=cos2θ

=

cosθ

sinθ

=tanθ

Step-by-step explanation:

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