2 sin square30- 3 cos square 45 + tan square 60
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sin 30=1/2
cos 45=1/√2
tan 60= √3
by substituting the values in the expression
2 sin square30- 3 cos square 45 + tan square 60
=2×(1/2)^2-3×(1/√2)^2+(√3)^2
= 2×1/4+-3×1/2+3
=1/2-3/2+3
=-2/2+3
=-1+3
=2
if any doubt comment or message
cos 45=1/√2
tan 60= √3
by substituting the values in the expression
2 sin square30- 3 cos square 45 + tan square 60
=2×(1/2)^2-3×(1/√2)^2+(√3)^2
= 2×1/4+-3×1/2+3
=1/2-3/2+3
=-2/2+3
=-1+3
=2
if any doubt comment or message
pepy:
did u understand?
yes thanks
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