2 sin² 30. tan 60 –3 cos² 60°. sec² 30°
Answers
Answered by
45
As we know that :-
» sin30 = 1/2
» tan60 = √3
» cos60 = 1/2
» sec30 = 2/√3
________________
Now,
=> 2sin²30.tan60 - 3cos²60.sec²30
Put the all values, we get :-
=> 2(1/2)²×√3 - 3(1/2)².(2/√3)²
=> 2×1/4×√3 - 3×1/4×4/3
=> √3/2 - 1
__________[ANSWER]
» sin30 = 1/2
» tan60 = √3
» cos60 = 1/2
» sec30 = 2/√3
________________
Now,
=> 2sin²30.tan60 - 3cos²60.sec²30
Put the all values, we get :-
=> 2(1/2)²×√3 - 3(1/2)².(2/√3)²
=> 2×1/4×√3 - 3×1/4×4/3
=> √3/2 - 1
__________[ANSWER]
Answered by
3
Answer:
As we know
sin 30° = 1/2
tan 60° = √3
cos 60° = 1/2
sec 30°= 2/√3
Now, 2x1/2x1/2x√3 - 3x1/2x1/2x2/√3x2/√3
2x1/4x√3 - 3x1/4x2/3
2/4x√3 - 3/4x2/3
2√3/4 - 1/2
2√3 - 2/4 = √3/4
THIS IS YOUR ANSWER
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