2 sin² theta - cos² theta =2 find theta
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Step-by-step explanation:
2(sin²-cos²)=2
2(1-cos²-cos2)=2
2-2cos²-cos²=2
-3cos²=0
thetha =pi
Answered by
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=> 2sin² a - cos² a = 2
=> 2sin² a - cos² a = 2 x 1
=> 2sin²a - cos²a = 2 (sin²a+cos²a)
=> 2sin² a - cos² a = 2sin²a + 2cos²a
=> 3 cos²a = 0
=> cos²a = 0
=> cos a = 0
=> cos a = cos 90°
=> a = 90°
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