Question

2.sin2A = √3 , then prove that 3 cot square A - 2 sinA = 8

Answer 1

Step-by-step explanation:

2sin2A=root3

sin2A=root3/2

sin2A=sin 60

2A=60

A=30

3cot^2 30-2sin30=3*3-2*1/2

=9-1=8 =RHS proved

Answer 2

||✪✪ QUESTION ✪✪||

2.sin2A = √3 , then prove that 3 cot square A - 2 sinA = 8

|| ✰✰ ANSWER ✰✰ ||

→ 2sin2A = √3

→ sin2A = (√3/2)

→ sin2A = sin60°

→ 2A = 60°

→ A = 30°

now, we have to Prove , 3 cot²A - 2sinA = 8

Taking LHS,

→ 3 cot²A - 2sinA

→ 3*cot²30° - 2*sin30°

→ 3(√3)² - 2*(1/2)

→ 3*3 - 1

→ 9 - 1

→ 8 = RHS .

✪✪ Hence Proved ✪✪