2 (sin6o + Cos6 (0) - 3(Sin4o + Cos4o)+ 1 = 0
Prove the above equation
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lick hereto get an answer to your question ✍️ Prove that 2(sin^6 theta + cos^6 theta) - 3(sin^4 ... Prove that 2(sin6θ+cos6θ)−3(sin4θ+cos4θ)+1=0.
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LHS = 2(sin ^6theta+cos^6theta) - 3(sin ^4theta+cos ^4theta ) + 1 = 2{(sin^2theta+cos^2theta)^3 - 3sin ^2thetacos ^2theta (sin ^2theta + cos ^2theta ...
Missing: Sin4o + Cos4o above
Step-by-step explanation:
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