Question

2( sin⁶thita + cos⁶ thita ) - 3( sin⁴ thita + cos ⁴ thita ) + 1 = 0
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Answer 1

Step-by-step explanation:

2( sin⁶∅+ cos⁶∅ ) - 3( sin⁴∅ + cos ⁴∅) + 1

2{(sin²)³+cos²)³}-3{(sin²)²+(cos²)²}+1

2(sin²+cos²)(sin⁴+cos⁴-sin²cos²)-3{(sin²+cos²)²-2sin²cos²)+1

2×1(sin⁴+cos⁴-sin²cos²)-3{(1)²-2sin²cis²}+1

2{(sin²)²+(cos²)²-sin²cos²}-3(1-2sin²cos²)+1

2{(sin²+cos²)²-2sin²cos²-sin²cos²}-3(1-2sin²cos²)+1

2({(1)²-3sin²cos²)-3(1-2sin²cos²)+1

2(1-3sin²cos²)-3(1-2sin²cos²)+1

2-6sin²cos²-3+6sin²cos²+1

3-3-6sin²cos²+6sin²cos²

0

#6-6-6