2 sinsquare theata minus cos square theta equal to 2
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Answer:
θ = 90°, 270°
Step-by-step explanation:
Given : 2 sin²θ - cos²θ = 2 ...(i)
{ As we know that,
sin²θ + cos²θ = 1 }
So, cos²θ = 1 - sin²θ ...(ii)
Using (ii) in (i), we get
→ 2 sin²θ - (1 - sin²θ) = 2
→ 2 sin²θ - 1 + sin²θ = 2
→ 3 sin²θ = 3
→ sin²θ = 1
→sinθ = √1
→ sinθ = 1
Also, sin 90° = 1 and sin 270° = 1
Therefore,
θ = 90°, 270°
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