Question

2.) solve: 3x/4-(x-1)/2=(x-2)/3​

Answer 1

Answer

x = 14.

Step-by-step explanation:

(3x-2x+2)/4 = (x-2)/3

(3x-2x+2)/4 = (x-2)/3(x+2)/4 = (x-2)/3

(3x-2x+2)/4 = (x-2)/3(x+2)/4 = (x-2)/33*(x+2) = 4* (x-2)

(3x-2x+2)/4 = (x-2)/3(x+2)/4 = (x-2)/33*(x+2) = 4* (x-2)3x+6 = 4x-8

(3x-2x+2)/4 = (x-2)/3(x+2)/4 = (x-2)/33*(x+2) = 4* (x-2)3x+6 = 4x-84x-3x = 6+8

(3x-2x+2)/4 = (x-2)/3(x+2)/4 = (x-2)/33*(x+2) = 4* (x-2)3x+6 = 4x-84x-3x = 6+8x = 14.

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Answer 2

Step-by-step explanation:

$\frac{3x}{4} - \frac{(x - 1)}{2} = \frac{(x - 2)}{3} .$

Multiply whole equation by LCM (12) :

$12 \times \frac{3x}{4} - 12 \times \frac{(x - 1)}{2} = 12 \times \frac{(x - 2)}{3} .$

$(3 \times 3x )- 6(x - 1) = 4(x - 2).$

$9x - 6x + 6 = 4x - 8.$

$- 3x - 4x = - 8 - 6.$

$- 7x = - 14.$

$x = \frac{ - 7}{ - 14} .$

$x = \frac{1}{2} .$

$x = 0.5$

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