Question

2. Solve 6x3 – 11x2 – 3x + 2 = 0 given that its roots are in harmonic progression.
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Answer 1

Answer:

Step-by-step explanation:

Consider the given equation,

6x3−11x2+6x−1=0

Put,x=1 we get

6.13−11.12+6.1−1=0

0=0

Hence, x=1 ⇒x−1=0 is zeroes os given equation.

Now

x−1)6x3−11x2+6x−16x2−5x+1

−(6x3−6x2)

−5x2+6x−1

−(−5x2+5x)

x−1

−(x−1)