Math, asked by viddhyanidhi8021, 5 hours ago



2)solve by substitute method
0.2x+0.3y=1.3
0.4x+0.5y=2.3

Answers

Answered by swetapanchal305
0

Answer:

x=3,y=2.2

Step-by-step explanation:

.4x+.6y=2.6

.4x+.5y=2.3

y=3

.4(3)+.5y=2.3

y=2.2

Answered by BrainlyTwinklingstar
4

Answer

\sf \dashrightarrow 0.2x + 0.3x = 1.3 \: \: --- (i)

\sf \dashrightarrow 0.4x + 0.5y = 2.3 \: \: --- (ii)

Multiplying the whole equation be 10,

\sf \dashrightarrow 2x + 3y = 13

\sf \dashrightarrow 4x + 5y = 23

By first equation,

\sf \dashrightarrow 2x + 3y = 13

\sf \dashrightarrow 2x = 13 - 3y

\sf \dashrightarrow x = \dfrac{13 - 3y}{2}

Now, let's find the value of y by second equation.

\sf \dashrightarrow 4x + 5y = 23

\sf \dashrightarrow 4 \bigg( \dfrac{13 - 3y}{2} \bigg) + 5y = 23

\sf \dashrightarrow \dfrac{52 - 12y}{2} + 5y = 23

\sf \dashrightarrow \dfrac{52 - 12y + 10y}{2} = 23

\sf \dashrightarrow \dfrac{52 - 2y}{2} = 23

\sf \dashrightarrow 52 - 2y = 23 \times 2

\sf \dashrightarrow 52 - 2y = 46

\sf \dashrightarrow -2y = 46 - 52

\sf \dashrightarrow -2y = -6

\sf \dashrightarrow y = \dfrac{-6}{-2}

\sf \dashrightarrow y = 3

Now, we can find the value of x by first equation.

\sf \dashrightarrow 2x + 3y = 13

\sf \dashrightarrow 2x + 3(3) = 13

\sf \dashrightarrow 2x + 9 = 13

\sf \dashrightarrow 2x = 13 - 9

\sf \dashrightarrow 2x = 4

\sf \dashrightarrow x = \dfrac{4}{2}

\sf \dashrightarrow x = 2

Hence, the values of x and y are 2 and 3 respectively.

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