2) Solve each of the following equations and check your solution by substituting its value in the equation. 1. -4(3-y)÷2=3(3+y)
Answers
Step-by-step explanation:
-4(3y)÷2=3(3+y)
-4(-y+3)÷2=3(3+y)
-2(-y +3)=3(3+y)
2y-6=3(3+y)
2y-6=3(3+y)
y= -15
Answer:
y= -36
Step-by-step explanation:
-4(3-y)÷2=3(3+y)
LHS = -4(3-y)/2 { simplify the brackets}
= -12 + 4y/2
RHS = 3(3+y)
= 9 + 3y
Equate them.
-12 + 4y/2 = 9 + 3y { there is a 2 in the denominator, so cross multiplication}
-12 + 4y = 2( 9 + 3y) Solve the brackets.
-12 + 4y = 18 + 6y { Transpose the terms }
-12 - 18 = 6y - 4y { + becomes - when it is transposed to the other side}
- 30 = 2y { bringing 2 to the other side}
- 30/2 = y
-15 = y
⇒ y = -15
Check
substituting -15 for y
LHS = -4(3- ( -15) / 2
= -4 ( 3 + 15) /2
= -12 - 60/2
= -72/2
= -36
RHS = 3(3+ (-15))
= 3( 3 -15)
= 9 -45
= -36
LHS = RHS
⇒ -36 = -36
Therefore y= -15.
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