Question

2. Solve for 'x' if

3 1 9

2x 2 6

x2 3 3

= 0​

Answer 1

Answer:

3 1 9 = Given equation,

3x = \frac{1}{9}3x=

9

1

On cross multiplying, we get

x = \frac{1}{27}x=

27

1

2×26 = x-2

2x + 2= 6

2x = 4

x = 4/2

×2 3 3 = Put all the variables on one side of the equal sign, then solve from there.

Explanation:

You want to get all the variables over to one side, so subtract 3 over to the right side. You should then get

x

2

=

−

3

.

You'd then square root both sides to get the simplified version of x.

√

x

2

=

√

−

3

The square root of

x

2

is simply x, but the

√

−

3

is more complicated, as you can't get the square root of a negative number. You'd have to involve

i

, or the idea of an imaginary number.

(Right now, we have

x

=

√

−

3

Because

i

=

√

−

1

, we could multiply our 3 and

i

.

If

√

−

3

=

3

⋅

√

−

1

=

3

i

, then

x

=

3

i

.