Question

2.
Solve for x
$\sqrt{6x + 7} - ( 2x-7)=0$​

Answer 1

Answer:

⇒ x = 1.5 (or) x = 7

Step-by-step explanation:

Given :

To solve for x,

if :

$\sqrt{6x+7} - (2x-7)=0$

Solution :

$\sqrt{6x+7} - (2x-7)=0$

⇒ $\sqrt{6x+7} = (2x-7)$

By squaring both the sides,

We get,

⇒ $(\sqrt{6x+7})^2 = (2x-7)^2$

⇒ $6x+7 = 4x^2 - 28x + 49$

⇒ $0 = 4x^2 - 34x + 42$

⇒ $0 = 4x^2 - 28x - 6x + 42$

⇒ $0 = 4x(x - 7) - 6(x - 7)$

⇒ $0 = (4x - 6)(x - 7)$

For the product to be 0,

Either,

4x - 6 = 0 (or) x - 7 = 0

⇒ 4x = 6 (or) x = 7

⇒ x = $\frac{6}{4}$ (or) x = 7

⇒ x = 1.5 (or) x = 7

Answer 2

Answer:

hope it is helpful to you