Question

2 solve the equation 8x-3=9-2x by transposing
method and verify the answer​

Answer 1

Answer:

6/5

Step-by-step explanation:

8x+2x=9+3

10x=12

x=12/10

x=6/5

Answer 2

Answer:

Given equation is $8x - 3 = 9 - 2x$

Transposing – 3 to RHS and it becomes 3 and -2x to LHS it becomes 2x

⇒ $8x + 2x = 9 + 3$

⇒$10x = 11$

Multiplying both side by $\frac{1}{10}$

⇒ $10x * \frac{1}{10} = 12 * \frac{1}{10}$

⇒ $x = \frac{12}{10}$

⇒ $x =$ $\frac{6}{5}$

By substituting  $\frac{6}{5}$ in the place of x in given equation, we get

$LHS = 8 * \frac{6}{5} - 3$

       $=$ $\frac{48}{5}$ $- 3$

       $=$ $\frac{48 - 15}{5}$

       $= \frac{33}{5}$

$RHS = 9 - 2 * \frac{6}{5}$

         $= 9 - \frac{12}{5}$

         $= \frac{45 - 12}{5}$

         $= \frac{33}{5}$

        ∴  $LHS = RHS$

                             Hope it helps you^_^