2. Solve the following linear equations. i) 3(t-3) = 5(2t - 1) ii) 8 (x-3) -(6-2x) = 2(x + 2) -
5(5 - X)
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1)Answer
Given, 3(t−3)=5(2t−1)
⟹ 3t−9=10t−5 ...[By Distribution Law]
⟹ 5−9=10t−3t ...[Transposing t terms to one side]
⟹ 7t=−4
⟹ t=
7
−4
.
2)Given, 8(x−3)−(6−2x)=2(x+2)−5(5−x)
8x−24−6+2x=2x+4−25+5x ...[By Distribution Law]
10x−30=7x−21 ...[On simplifying]
10x−7x=30−21 ...[Transposing x terms to one side]
3x=9
⟹ x=3.
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