Question

2. Solve the following pair of linear equations by substitution method:
i. 8x + 5y = 11 and 3x – 4y = 10
ii. 2x = 5y + 4 and 3x – 2y + 16 = 0​

Answer 1

Step-by-step explanation:

8x +5y =11

13xy =11

xy= 11-13

xy= -2

Answer 2

Answer:x=2,y=-1

Step-by-step explanation:

8x+5y=11•••••equation 1

x=(11-5y)/8

Now,putting the value of x in equation 2

3x-4y=10

3{(11-5y)/8}-4y=10

(33-15y-32y)8=10

33-47y=80

-47y=80-33

y=-1

Now, putting the value of y in eqn 1:

x=(11-5y)/8

x={11-5(-1)}/8

x=(11+5)/8

x=16/8

x=2