Question

2. Solve the following pairs of linear equations,
graphically and find nature of the solution :
(i) x + y = 3; 3x – 2y = 4 (ii) 2x – y = 4; x + y = -1
(iii) x + y = 5;' 2x + 2 y = 10
(iv) 3x + y = 2; 2x – 3y = 5​

Answer 1

X+Y=3,3x-2y=4

(i) X+Y =3

* when, X=0

0+Y= 3

Y = 3 ( Cordinates (0, 3)

* When, X = 3

3 + Y = 3

Y= 0 Cordinates ( 3,0)

(ii) 3x - 2 Y =4

* when ,X=0

3 ( 0) - 2 Y =4

2Y = -4

Y = -2 Cordinates ( 0,-2)

* When , X = 2

3( 2) - 2 Y = 4

2Y = 2

Y = 1 Cordinates ( 2,1)

The Intersecting Point as shown on the Graph is ( 2,1)

Answer = X = 2,

Y = 1

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