Question

2. Solve the following question : (1 mark) What is the ratio of the areas of two triangles with equal heights, if their respective bases are of length 4 cm and 8 cm?​

Answer 1

Answer:

A1: A2= 1:2

Step-by-step explanation:

$area \: of \: first \: triangle = \frac{1}{2} \times 4 \times h \\ \\ a1 \ = 2h \\ \\ \\ a2 = \frac{1}{2} \times 8h \\ \\ = 4h \\ \\ \\ \frac{a1}{a2} = \frac{2h}{4h} = \frac{1}{2}$

Answer 2

Answer:

a2 = 1/2×8h

= a2×4H

a2+A1= 4h= 2 h