Question

2] Solve the following simultaneous equation.
3x - 3y = 8 ; 3x + y = 2​

Answer 1

Step-by-step explanation:

3x-3y=8 eq1

3x+y=2 eq2

1-2

3x-3y-(3x+y)=8-2

3x-3y-3x-y=6

-4y=6

y=6/-4

=3/-2

3x+y=2

3x-3/2=2

3x=2+3/2

3x= 7/2

x=7/6

Answer 2

▬▬▬▬▬▬▬▬▬ஜ۩۞۩ஜ▬▬▬▬▬▬▬▬

The ans is :—

3x – 3y = 8 ———— ( 1 )

3x + y = 2 ———— ( 2 )

$= > 3x - 3y = 8 \\ = > 3(x - y) = 8 \\ = > x - y = \frac{8}{3} \\ = > x = \frac{8 + 3y}{3}$

Putting the value of x in eqn (2)

$= > 3x + y = 2 \\ = > 3( \frac{8 + 3y}{3} ) + y = 2 \\ = > 8 + 4y = 2 \\ = > 4y = - 6 \\ = > y = - \frac{6}{4}</em></strong><strong><em> </em></strong><strong><em>\</em></strong><strong><em>\</em></strong><strong><em> </em></strong><strong><em>=</em></strong><strong><em> </em></strong><strong><em>></em></strong><strong><em> </em></strong><strong><em>y</em></strong><strong><em> </em></strong><strong><em>=</em></strong><strong><em> </em></strong><strong><em>-</em></strong><strong><em> </em></strong><strong><em> </em></strong><strong><em>\</em></strong><strong><em>frac</em></strong><strong><em>{</em></strong><strong><em>3</em></strong><strong><em>}</em></strong><strong><em>{</em></strong><strong><em>2</em></strong><strong><em>}</em></strong><strong><em>$

So the value of x is

$= > x = \frac{8 + 3y}{3} \\ = > x = \frac{8 + 3( - \frac{ </em></strong><strong><em>3</em></strong><strong><em>}{</em></strong><strong><em>2</em></strong><strong><em>}) }{3} \\ = > x = \frac{</em></strong><strong><em>7</em></strong><strong><em>}{</em></strong><strong><em>6</em></strong><strong><em>}$