Question

(2) Solve the following simultaneous
(i) 2x + y = 5; 3x - y = 5.
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Answer 1

2x+ y=5....(1)

3x -y =5....(2)

adding equation (1) and (2)

2x + y = 5

+ 3x - y = 5

__________

5x = 10

x = 10 /5

x = 2

substituting x=2 in equation (1)

2×2+y=5

4+y=5

y=5-4

y=1

Hope it helps you....☺☺

Answer 2

Answer:

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Explanation:

Step 1: 2x+y=5  ......(1)

           3x-y=5   .......(2)

Step 2: 3(2x+y=5)

            2(3x-y=5)

therefore, 6x+3y=15

                 6x-2y=10

Step 3: Subtract both the Equations:

     You will get:

                       5y=5

                          y=1

Step 4: Now in Eq.2:

            Substitute the value of y.

                  2x+y=5

                     2x+1=5

                     2x=5-1

                     2x=4

                     x=4/2

                     x=2

Now you get,

               x=2 ang y=1