Question

2. solve the following simultaneously equation
(1) 3a+5b=26; a+5b=22
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Answer 1

Answer:

a=2

b=4

Step-by-step explanation:

a+5b=22-----------------------eq.1

3a+5b=26----------------------eq.2

subtract eq.1 and eq.2

2a=4

=>a=2

subsituta a=2 in eq.2

2+5b=22

=>5b=20

=>b=4

Answer 2

Answer:

a=2 and b=4

Step-by-step explanation:

a+5b=22

3a+5b=26

by elimination method

a+5b=22

3a+5b=26

=-2a=-4

a=4/2

a=2

sub a in equation 1

2+5b=22

5b=22-2

5b=20

b=20/5

b=4