Question

2. solve the following simultaneously equation
(1) 3a+5b=26; a+5b=22
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Answer 1

Answer:

$\\ \\ 5a + 5b = 26 \\ a + 5b = 22 \\ { = }^{ - } { = }^{ - } { = }^{ - } \\ 4a = 4 \\ \\ a = 1 \\ \\ \\ and \\ \\ \\ a +5 b = 22 \\ \\ 1 + 5b = 22 \\ \\ 5b = 21 \\ \\ b = \frac{21}{5}$

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Answer 2

Answer:

3a + 5b = 26; .....(I)

a + 5b = 22 .....(II)

Subtracting (II) from (I)

2a = 4

⇒ a = 2

Putting the value of a = 2 in (II)

5b = 22 - 2 = 20

⇒b = 20/5

=4

Thus, a = 2 and b = 4.