Question

2) Solve using method of elimination :
(a) x + 2y = -4
3x - 5y = -1​

Answer 1

Answer:

x+2y=-4(I)

3x-5y=-1(ii)

(I)×3-(ii)

3x+6y=-12

3x-5y=-1

3x cancelled we find

11y=-11

y=-1

y put in (I)

x-2=-4

x=-4+2

x=-2

-2,-1