2 sound waves having a phase difference of 60 degree have path difference of
Answers
Answered by
1
We know the relation between path difference , phase difference and wavelength of wave is given by
∆Ф = 2π/λ ∆x
Here ∆Φ is phase difference , ∆x is path difference and λ is wavelength of wave.
Given, ∆Φ = 60° = 60° × π/180° = π/3 rad
Wavelength is not mentioned so, assumed wavelength is λ
Now, π/3 = 2π/λ ∆x
∆x = λ/6
Hence path difference is λ/6
∆Ф = 2π/λ ∆x
Here ∆Φ is phase difference , ∆x is path difference and λ is wavelength of wave.
Given, ∆Φ = 60° = 60° × π/180° = π/3 rad
Wavelength is not mentioned so, assumed wavelength is λ
Now, π/3 = 2π/λ ∆x
∆x = λ/6
Hence path difference is λ/6
Similar questions