2. Speedup (S) is equal to
Mark only one oval.
1.)Ts/ TP
2.)Ts * Tp
3.)TS + TP
4.)Ts - Tp
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answer: TS/TP
Explanation:
Let Speedup be S, old execution time be T, new execution time be T’ , execution time that is taken by portion A(that will be enhanced) is t, execution time that is taken by portion A(after enhancing) is t’, execution time that is taken by portion that won’t be enhanced is tn, Fraction enhanced is f’, Speedup enhanced is S’.
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