Question

2 springs of force constant 1000 N/m and 2000N/m are sreched by same force. Find the ratio of their respective potential energies

Answer 1

Answer: the answer is 2:1

Explanation:

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Answer 2

Answer:

2:1

Explanation:F= -kx

k=spring constant. P.E= -1/2kx^2 (in case of spring). From above equation. P.E=1/2F^2/K,. So, Ratio of potential energy=k2/k1. P.E=2000/1000. P.E=2/1