2. Square of 2x^2 - 3y^2 is
(a) 4x2 - 9y4
(b) 4x4 + 9y4 + 12x2y2
(c) 4x4 + 9y4 – 12x2y2
(d) 4x4 + 9y4
Answers
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(a-b)^2 =a^2-2ab+b^2
Therefore:
=(2x^2)^2-2(2x^2)(3y^2)+(3y^2)
=4x^4 - 12x^2 y^2 + 9y^4
I think this is the answer
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