Question

2 stones of mass m1 and m2 are dropped from 2h and h their momentum on reaching ground is​

Answer 1

Answer:

From second equation of motion,

s=ut+

2

1

at 2

Given, u=0, a=g, s 1

=h 1 , s 2

=h 2h 1

=(1/2)g(t 1 ) 2h 2

=(1/2)g(t 2 ) 2

So, h

1/h 2

=(t 1 ) 2/(t 2 ) 2or(t 1 )/(t 2)= h 2h 1

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