2 students appeared in an examination. One of them secured 9 marks more than the other and his marks were 56% of the sum of their marks. Find the marks obtained by both.
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x=9+y (1)
x=(56/100)(x+y) (2)
By substituting equation 1 in 2 we get
x=42 and
y=35
x=(56/100)(x+y) (2)
By substituting equation 1 in 2 we get
x=42 and
y=35
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