2 students stand side by side at a distance of 480m from a wall , student a claps her hands and student b records the time taken to hear the echo as 2.9 secs , calculate the speed of sound
Answers
Answer:
331.03 m/s
Explanation:
Given :
- Distance between the two walls = 480 metres
- Time taken to hear the echo = 2.9 seconds
To find :
- Speed of the sound in the above case
Here distance will be double the distance between the wall and the students as the echo has to go and again come back
Distance = 2×480
Distance = 960 metres
Time taken = 2.9 seconds
Speed = distance / time
Speed = 960/2.9
Speed = 331.03 m/s
The speed of the sound in the above case is equal to 331.03 m/s
AnswEr :
Given that distance of student A from wall is 480 m. Echo heard after 2.9 seconds.
We have to find speed of sound.
Here we have,
➡ Distance (d) = 480 m [B/w student & wall]
➡ Time (t) = 2.9 s
➡ Speed of sound = ?
Concept :
↗ Speed of object is defined by the division of distance & time taken.
↗ Speed = Distance/Time [s = d/t]
Now as the echo has to be heard, so that will have to travel the same distance twice.
→ Distance = 2 × 480
→ Distance = 960 m
So using that formula :-
→ Speed = Distance/Time
Substituting values,
→ Speed = 960/2.9
→ Speed = 331.03
→ Speed = 331.03 m/s
∴ Speed of sound = 331.03 m/s [Answer]