Question

2) Subtract the sum of x + y and x - z from the sum of x-2z and x + y + Z.​

Answer 1

$(x - 2z) + (x + y + z) - [(x + y) + (x - z)]$

$= x - 2z + x + y + z - {x + y + x - z}$

$=x - 2z + x + y + z - x - y - x + z$

$=x + x - x - x + y - y + z + z - 2z$

$= 0$

❤@gumnaambadshah❤

Answer 2

Answer:

(x−2z)+(x+y+z)−[(x+y)+(x−z)]

= x - 2z + x + y + z - {x + y + x - z}=x−2z+x+y+z−x+y+x−z

=x - 2z + x + y + z - x - y - x + z=x−2z+x+y+z−x−y−x+z

=x + x - x - x + y - y + z + z - 2z=x+x−x−x+y−y+z+z−2z

= 0=0