Math, asked by babishansingh78, 1 month ago

2) Sum of the ages of father and son is 68. After 8 years
father will be thrice as old as son. The present age
(in years) of the son is
A) 18
B) 16
C) 15
D) 13​

Answers

Answered by RvChaudharY50
2

Question :- Sum of the ages of father and son is 68. After 8 years father will be thrice as old as son. The present age

(in years) of the son is :-

A) 18

B) 16

C) 15

D) 13

Answer :-

Let us assume that, Present age of son is x years.

so,

→ Father's age = (68 - x) years.

now,

→ After 8 years son will be = (x + 8) years old.

→ After 8 years father will be = (68 - x) + 8 = (76 - x) years old.

A/q,

→ Father = 3 * son

→ (76 - x) = 3(x + 8)

→ 76 - x = 3x + 24

→ 76 - 24 = 3x + x

→ 4x = 52

→ x = 13 years. (D) (Ans.)

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Answered by amitnrw
2

Given : Sum of the ages of father and son is 68.

After 8 years father will be thrice as old as son.

To Find: The present age (in years) of the son is

A) 18

B) 16

C) 15

D) 13​

Solution:

Sum of the ages of father and son is 68.

Son age  = S years

Father age = 68 - S  years

After 8 years Son = S + 8

After 8 years father = 68 - S + 8  = 76 - S

After 8 years father will be thrice as old as son.

=> 76 - S = 3(S + 8)

=> 76 - S = 3S + 24

=> 4S  = 52

=> S = 13

present age (in years) of the son is  13 Years

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