Question

2. Sum of two numbers is 50. If one of the number is 10 more than the other, find the numbers​

Answer 1

Let the two numbers be x, y.

x+y = 50 [Eq 1]

x-y = 10 [Eq 2]

x = 50-y [From Eq - 1]

Substitute this value in Eq 2

x-y = 10

50-y -y = 10 [Add two negative numbers and assign a - sign]

50–2y = 10 [As numbers are transposed from one to another side their sign changes]

50 -10 = 2y

40 = 2y

Dividing by 2 both sides

40/2 = 2y/2

20 = y

x = 50-y

x = 50–20 = 30

x = 30, y = 20 :Final Answer

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