Question

2. Surface area of a cylindrical water container is 2 m². It
is filled up to the height 1.5 m. What is the pressure at
the bottom of the container ? What is thrust of water at
the bottom of container ? Ignore atmospheric pressure.
Density of water = 1000 kg m-3.
11500 kof/m2: 3000 kgf]​

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11th

Physics

Mechanical Properties of Fluids

Pressure

A rectangular tank of base ...

PHYSICS

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Asked on December 20, 2019 by

Abhinab Ganeshan

A rectangular tank of base area 100 m

2

has a height of 2 m. Calculate the thrust at the bottom of the tank, if it is filled upto the brim with water of density 10

3

kg m

−3

.

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ANSWER

Given that,

density of water (ρ)=10

3

Kg/m

3

water fixed up till height (h)=2 m

Area of base (A)=100 m

2

.

assuming atmospheric pressure (P

0

)=1 atm≃10

5

Pa

so, pressure at bottom of tank,

P=P

0

+ρgh.

=10

5

+10

3

×10×2[g=10 m/s

2

]

P=(1.2×10

5

) Pa

Thus, thrust on bottom surface,

F=P.A=(1.2×10

5

)×10

2

⇒F=1.2×10

7

N