Question

2 tables and 3 chairs together cost 2000 where 3 table and 2 chair together cost 2500.find the total cost of one table and 5 chair find using elimination method

Answer 1

Let, cost of each table is x rupees and cost of each chair is y rupees. Therefore, from the first information 2x+3y=2000 ....(1) and from the second information 3x+2y=2500 ....(2) from (2)-(1) x-y=500. Therefore x=500+y putting the value of x in (2). 2(500+y) + 3y=2000 =>1000+2y+3y=2000 =>5y=1000 =>y=200 so,x= 500+y=500+200=700
So total cost of one table and five chair, x+5y=700+5(200)=1700 rupees