Question

2 tables and 3 chairs together cost 2000 whereas 3 tables and 2 chairs together cost 2500 rupeese . find the cost of 1table and 5 chairs by the method of substitutional method ​

Answer 1

Answer:

let the table be x and chair be y

2x+3y=2000 -----------eq(1)

3x+2y=2500 -----------eq(2)

2x=2000-3y

x=(2000-3y)/2

put the value of x= (2000-3y)/2 for now ,

3[(2000-3y)/2]+2y = 2500

(6000-9y)/2 +2y = 2500

(6000-9y+4y)/2 = 2500

6000-5y = 5000

-5y = 5000-6000

y= -1000/-5

y = 200;

put the value of y in eq(1)

2x + 3*200=2000

2x=2000-600

x=1400/2

x=700;

so , the cost of 1 chair is 200

the cost of 1 table is 700

1×700+5×200=1700;

I hope this will help u ;