2 tables and 3 chairs together cost Rs. 2000 whereas 3 tables and 2 chairs together cost Rs. 2500.
Find the total cost of 1 table and 5 chairs solving the equations graphically.
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Given :
• 2 tables and 3 chairs together cost Rs. 2000 whereas 3 tables and 2 chairs together cost Rs 2500
To Find :
• The cost of 1 table and 5 chairs.
Solution :
According to the question,
Let,
- The cost of 1 table and 1 chair be x & y.
2x + 3y = 2000 ...(i)
3x + 2y = 2500 ...(ii)
From equation (i),
2x + 3y = 2000
x = 2000 - 3y/2
Putting the value of x in equation (ii)
→ 3x + 2y = 2500
→ 3(2000 - 3y/2) + 2y = 2500
→ 6000 - 9y/2+ 2y = 2500
→ 6000 - 9y + 4y = 2500 × 2
→ 6000 - 5y = 5000
→ -5y = 5000 - 6000
→ -5y = - 1000
→ y = 200
Substituting the value of x in equation (i)
→ 2x + 3y = 2000
→ 2x + 3(200) = 2000
→ 2x + 600 = 2000
→ 2x = 1400
→ x = 700
So, the cost of 1 table is Rs 700
and the cost of 5 chair is 5 × 200 = Rs 1000
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