2. Take a soft wire. Measure it^ prime s length. Make a square, a circle, an equilateral triangle and find their circumference perimeters. Verify that they are equal.
Answers
Answered by
0
Answer:
please give me Brainliset answer
Step-by-step explanation:
Let the perimeter of each figure be P cm.
Then, side of equilateral triangle
3
P
Side of square =
4
P
Radius of circle =
2π
P
∴T=
4
3
×(
3
P
)
2
=
36
3
P
2
S=(
4
P
)
2
=
16
P
2
C=π×(
2π
P
)
2
=
4π
P
2
=
88
7P
2
=0.0795P
2
⇒T=
36
3
P
2
=
36
1.732
P
2
=0.0481P
2
S=0.0625P
2
C=0.0795P
2
∴C>S>T
Answered by
2
Step-by-step explanation:
Let the perimeter be p, radius of circle be r and side length of square and triangle be a and b respectively.
p=2πr=4a=3b
so r=p2π,a=p4,b=p3
area of circle = πr2=p24π
area of square = a2=p216
area of triangle = 3√4b2=p2123√
Since 4π<16<12 3–√ , area of circle > square > triangle.
In fact, for a given perimeter, a circle has the largest area of all possible figure
Similar questions