Math, asked by sonu42525, 10 months ago

2 tam 30°/1- tan 30° =√3​

Answers

Answered by harnoor92
0

Answer:

2 \tan(30)  \div 1 -  \tan(30)  =  \sqrt{3}  \\ 2(1 \div  \sqrt{3} ) \div 1 - 1 \div  \sqrt{3}   =  \sqrt{3} \\ 2 \div  \sqrt{3}  \times 1 - 1 \div  \sqrt{3}  =  \sqrt{3}  \\ 2 \div  \sqrt{3}  - 1  \div   \sqrt{3}  =  \sqrt{3}   \\ 2 - 1 \div  \sqrt{3} =  \sqrt{3}   \\ 1 \div  \sqrt{3}  =  \sqrt{3} =  \sqrt{3}   \\  \sqrt{3}  =  \sqrt{3}  \div 1 \\  \sqrt{3}  =  \sqrt{3}

LHS =RHS

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Answered by aditya859536
0

Answer:

2 tan30°/1- tan 30°

[tan30° =1/√3]

(2×1/3)

1-1/√3

2

3

3-1

3

= 2/√3-1

Answer ={2/√3-1}

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