Question

2+tan^2+cot^2÷sec×cosec​

Answer 1

Step-by-step explanation:

2+ tan^2 X + cot^2 X) / (secx* cosecx)

={2+ (Sec^2 X - 1) +( cosec^2 X- 1) }/ ( secx* cosecx)

={sec^2 X. + cosec^2 X }/ ( secx* cosecx)

=SecX/ Cosecx + cosecx/secx

=tanx + cotx

=

\frac{ { \sin(x) }^{2} + { \cos(x) }^{2} }{sinx. \cos(x) }

sinx.cos(x)

sin(x)

2

+cos(x)

2

=cosecx * secx [Ans]

Hope it will help you. Mark it Brainliest Answer.